x^2+0.16x-0.32=0

Solution for x^2+0.16x-0.32=0 equation:

x^2+0.16x-0.32=0

a = 1; b = 0.16; c = -0.32;
Δ = b2-4ac
Δ = 0.162-4·1·(-0.32)
Δ = 1.3056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.16)-\sqrt{1.3056}}{2*1}=\frac{-0.16-\sqrt{1.3056}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.16)+\sqrt{1.3056}}{2*1}=\frac{-0.16+\sqrt{1.3056}}{2}
$